A gramophone record is revolving with an angu | vedclass

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(C) For the coin to revolve with the record without slipping,the required centripetal force must be provided by the static friction force.The centripe

Vedclass · Accepted Answer

$r \le \frac{\mu g}{\omega^2}$

Vedclass · Answer

(C) For the coin to revolve with the record without slipping,the required centripetal force must be provided by the static friction force.The centripetal force required is $F_c = mr\omega^2$.The maximum static friction force available is $f_{s,max} = \mu N = \mu mg$.For the coin to stay in place,the friction force must be greater than or equal to the required centripetal force:$f_{s,max} \ge F_c$$\mu mg \ge mr\omega^2$Dividing both sides by $m\omega^2$ (where $m$ is the mass of the coin),we get:$r \le \frac{\mu g}{\omega^2}$

$A$ gramophone record is revolving with an angular velocity $\omega$. $A$ coin is placed at a distance $r$ from the centre of the record. The static coefficient of friction is $\mu$. The coin will revolve with the record if

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